In the title molecule, C 10H 11NO 2, the benzene ring forms dihedral angles of 33.15 (2) and 6.20 (2)° with the mean planes of the amide and propenoxy groups, respectively. The amide –NH 2 group is oriented toward the propenoxy substituent and forms a weak intramolecular N—H⋯O hydrogen bond to the propenoxy O atom. The conformation of the propenoxy group at the C sp 2—C sp 3 and C sp 3—O bonds is synperiplanar and antiperiplanar, respectively. In the crystal, N—H⋯O hydrogen bonds involving the amide groups generate C(4) and R 2 3(7) motifs that organize the molecules into tapes along the a-axis direction. There are C—H⋯π interactions between the propenoxy –CH 2 group and the aromatic system of neighboring molecules within the tape. The mean planes of the aromatic ring and the propenoxy group belonging to molecules located on opposite sites of the tape form an angle of 83.16 (2)°.